Crosswind component
Wind 25 kt at 40° off the runway heading.
XWC = wind speed × sin(angle)
- Keys
- 25 * 40 sin =
- Screen
- 16.07 kt
The formulas you type most in the pilot theory exams, solved key by key on the exam calculator. The results are not typed by hand: they are computed by the same engine we checked against the official calculator, so they are what you will see on the screen. Press «Try it» and the sequence types itself on the calculator.
The data in each example is made up and the factors (27 ft/hPa, 120 ft/°C, 101.3, 3.785…) are the usual ones: always use those your question gives you. This is calculator-handling practice, not a syllabus.
Wind 25 kt at 40° off the runway heading.
XWC = wind speed × sin(angle)
Same wind: 25 kt at 40°.
HWC = wind speed × cos(angle)
Crosswind of 16 kt with a TAS of 120 kt. Division first, then = and finally asin.
sin(WCA) = XWC ÷ TAS
Track 270° plus the WCA above. If asin ends up as the second number of the addition, the calculator glues the numbers together.
Heading = track + WCA
TAS 120 kt and the earlier 25 kt wind at 40°. The headwind component is subtracted.
GS = TAS − wind speed × cos(angle)
187 NM at a GS of 142 kt.
minutes = distance ÷ GS × 60
4 NM off track after 50 NM.
track error = distance off × 60 ÷ distance gone
Change of longitude of 5° at latitude 45°.
departure (NM) = ch. long in minutes × cos(latitude)
Change of longitude of 20° at mean latitude 50°.
convergency = ch. long × sin(mean latitude)
35 minutes at a GS of 142 kt.
distance = GS × minutes ÷ 60
The same 20° change of longitude at mean latitude 50°: half the convergency.
CA = ch. long × sin(mean latitude) ÷ 2
TAS 150 kt with 25° of bank. The square is done with x^2 and the tangent goes inside the brackets.
radius (ft) = TAS² ÷ (11.26 × tan(bank))
The same 150 kt and 25° of bank.
rate (°/s) = 1091 × tan(bank) ÷ TAS
Elevation 2300 ft and QNH 998 hPa, with 27 ft per hPa (use 30 if your question says so).
PA = elevation + (1013 − QNH) × 27
PA 5000 ft and ISA deviation +15 °C.
DA = PA + 120 × ISA deviation
Outside air temperature −40 °C. The sign goes AFTER the number, and the root after the =.
LSS = 38.95 × √(temperature in K)
8000 ft. ISA falls 2 °C per 1000 ft from +15 °C.
ISA = 15 − 2 × (altitude ÷ 1000)
OAT of −10 °C at 8000 ft. The sign goes AFTER the 10 and ISA is worked out inside brackets.
deviation = OAT − ISA
TAS 450 kt with a local speed of sound of 590 kt.
M = TAS ÷ LSS
45 US gal with specific gravity (SG) 0.72.
kg = US gal × 3.785 × SG
Rate of climb 900 ft/min at a GS of 110 kt.
gradient % = ROC ÷ (GS × 101.3) × 100
200 kg on board, burn of 12 kg/min for 3.5 min and 15 kg taxi fuel. The calculator groups the subtraction wrongly.
remaining = on board − burn × time − taxi
180 kg of usable fuel at a burn of 42 kg/h.
minutes = fuel ÷ burn × 60
GS 140 kt at a burn of 42 kg/h.
NM per kg = GS ÷ burn
Trip fuel 95 kg, 5 % contingency and 30 min final reserve at 42 kg/h.
total = trip × 1.05 + burn × 0.5
GS 120 kt on approach.
ROD (ft/min) = GS × tan(3°) × 101.3
Three masses (650, 80 and 120 kg) with arms 2.1, 2.4 and 3.0 m. Each moment is added to memory with M+ and the total is divided by the total mass (850 kg).
CG = total moment ÷ total mass
CG at 3.25 m, leading edge of the MAC (LEMAC) at 2.9 m and MAC of 1.4 m.
%MAC = (CG − LEMAC) ÷ MAC × 100
Total mass 850 kg, the CG must move 0.05 m and the load is shifted 2.1 m.
mass to move = total mass × ΔCG ÷ shift distance
850 kg with CG at 3.25 m; 70 kg are added at arm 4.1 m.
new CG = (M × CG + m × arm) ÷ (M + m)
Repeat each sequence on the calculator with the «Study helper» on and, once you can do them without looking, switch to «Exam mode». If you want to know why the two traps fail, they are explained in every quirk of the official calculator.